In how many ways can 12 people sit around a table so that all shall not have the same neighbors in any two arrangements?
Asked by yogeshkumar pathak | 31st Jan, 2019, 11:56: PM
12 people can sit around a table in
(12 – 1)! = 11!
However, each person will have the same neighbour in clockwise and anticlockwise arrangements.
Therefore, the required number is
= 7! / 2
= 2520 ways
Answered by Science Mate | 1st Feb, 2019, 01:41: AM
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