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Asked by kumariannu5478 | 20 May, 2023, 08:43: PM
answered-by-expert Expert Answer
Dear Student,
 

The ionic reactions for given reaction are,

2/3 × (2Al3+) + 4e− → 4/3Al

2/3 × (3O2−) → O2 + 4e−

Therefore, the number of electrons transferred, n = 4

ΔF = −nFe⁻ = −4 × 96500 × E

966 × 103 = −4 × 96500 × E

E = −2.5 V

Answered by | 22 May, 2023, 09:28: AM

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