if (x-2)is a factor of X3+ax2+bx+16 and b=4a.find a and b.

Asked by  | 20th May, 2012, 05:44: PM

Expert Answer:

if x-2 is a factor then, f(2) = 0
That is, 8+4a+2b+16 = 0
Or, 4a+2b = -24
Or, 4a + 8a = -24
Or, 12a = -24
Or, a = -2
And, b = 4(-2) = -8.
 

Answered by  | 20th May, 2012, 08:50: PM

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