Request a call back

if we increase kinetic energy by 20%, then find percentage increase in linear momentum
Asked by kaziryan.05 | 19 May, 2021, 07:43: AM
If v is speed of particle and m is mass of particle , then Kinetic energy K is given as

K = (1/2) m v2

Momentum p = ( m v )

If we eliminate v and write kinetic energy in terms of momentum , we get

K = p2 / ( 2 m )

If we take logarithm on both side and differentiate , we get

ln(K) = ln(1/2m) +  2 ln(p)

dK/K  = 2 ( dp/p )

Hence if change in kinetic energy is 20%  ,  dK/K = 0.2 .

Hence change in momentum ( dp/p ) = 0.1  or change in momentum 10%
Answered by Thiyagarajan K | 19 May, 2021, 09:11: AM

Application Videos

CBSE 9 - Physics
Asked by topperlearningforcontent | 31 Jan, 2022, 10:14: AM
CBSE 9 - Physics
Asked by tajbindarkaurs | 14 Nov, 2021, 10:19: AM
CBSE 9 - Physics
Asked by kaziryan.05 | 19 May, 2021, 07:43: AM
CBSE 9 - Physics
Asked by parthmalikschool | 24 Nov, 2020, 12:45: AM
CBSE 9 - Physics
Asked by swatipuspapatel | 31 May, 2020, 12:23: PM
CBSE 9 - Physics
Asked by matoriark | 29 Mar, 2020, 02:21: PM