a bus of mass 10000kg with a velocity of 90 km/h. calculate work done to stop the bus

Asked by parthmalikschool | 24th Nov, 2020, 12:45: AM

Expert Answer:

mass of bus = 10000 kg 
velocity of bus = 90 km/h = 25 m/s 
Work done = Change in kinetic energy 
F i n a l space K i n e t i c space e n e r g y space minus space I n i t i a l space k i n e t i c space e n e r g y space
W o r k space d o n e space equals space 1 half m v squared minus 1 half m u squared
W h e n space b u s space c o m e s space t o space s t o p space t h e space v e l o c i t y space b e c o m e s space z e r o
T h u s comma space
v space equals space 0 space
T h u s comma space
W o r k space d o n e space equals space 0 space minus space 1 half m u squared space equals space 1 half cross times open parentheses 10000 close parentheses cross times open parentheses 25 close parentheses squared space equals space 31 comma 25 comma 000 space J space equals space 3125 space k J space

Answered by Shiwani Sawant | 24th Nov, 2020, 11:57: AM