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CBSE Class 9 Answered

An elevator is designed to lift a load of 1000 kg with uniform velocity of 2m/s . Power of the elevator will be?
Asked by tajbindarkaurs | 14 Nov, 2021, 10:19: AM
Expert Answer
Since the load is lifted with constant speed , Force F = mg = 1000 × 9.8 = 980 N
 
where m is mass of load and g is acceleration due to gravity.
 
Power = force × speed = 980 × 2 = 1960 W
Answered by Thiyagarajan K | 14 Nov, 2021, 03:01: PM
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