if the sum of the zeros of the polynomials 2x2-kx+9/2 is twice the product of zeros.find the value of k.

Asked by Renoy Gladson | 9th May, 2013, 12:15: PM

Expert Answer:

2x2-kx+9/2  = 0
For any quadration equation ax^2 + bx + c = 0, sum of roots = -b/a and product of roots  = c/a
Hence, here, sum of roots = k/2 and product of roots = 9/4
Also, since its given that the sum of the roots is twice the product of the roots
Hence, k/2 = 2*9/4
hence, k = 9

Answered by  | 10th May, 2013, 05:24: AM

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