if the sum of the zeros of the polynomials 2x2-kx+9/2 is twice the product of zeros.find the value of k.

2x2-kx+9/2  = 0

 

For any quadration equation ax^2 + bx + c = 0, sum of roots = -b/a and product of roots  = c/a

 

Hence, here, sum of roots = k/2 and product of roots = 9/4

Also, since its given that the sum of the roots is twice the product of the roots

 

Hence, k/2 = 2*9/4

hence, k = 9