if o is the centre of the crcle of radius R and AB is a chord of the circle at a distance r/2 from O, then angle BAO=???

Asked by vedant sharma | 18th Feb, 2014, 06:30: PM

Expert Answer:

Consider the above figure.
 
The line from the centre to the chord is a perpendicular bisector of the chord.
 
Thus OM is perpendicular to AB and triangle MAO is a right triangle.
 
Given that OA = r (radius) and O M equals r over 2
Consider
sin open parentheses angle B A O close parentheses equals fraction numerator o p p over denominator h y p end fraction rightwards double arrow sin open parentheses angle B A O close parentheses equals fraction numerator r over denominator begin display style 2 over r end style end fraction equals 1 half rightwards double arrow sin open parentheses angle B A O close parentheses equals 1 half rightwards double arrow angle B A O equals begin inline style 30 end style begin inline style degree end style

Answered by  | 19th Feb, 2014, 10:36: AM

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