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if hcf of 210 and 55 is expressible in the form 210×5-55x, find x
Asked by harshvsk05 | 03 Apr, 2020, 11:59: AM Expert Answer

210 = 55 × 3 + 45  ... (1)
55   = 45 × 1 + 10  ... (2)
45   = 10 × 4 + 5
10   = 5 × 2 + 0

HCF(210, 35) =5 = 210×5-55x

5 = 45 -  10 × 4
= 210 - 55 × 3  - (55 - 45)4       .... from (1) and (2)
= 210 - 55 × 3  - 55 × 4 + 45 × 4
= 210 - 55 × 7 + (210 - 55 × 3)× 4  ... from (1)
= 210 × 5 - 55 × 19
Answered by Yasmeen Khan | 03 Apr, 2020, 01:04: PM

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