CBSE Class 10 Answered
if d is the HCF of 45 and 27 find x and y satisfying d=27x+45y?
Asked by bhavikabhatia1125 | 29 May, 2021, 04:12: PM
Expert Answer
HCF of 45 and 27 can be calculated as follows.
45 = 27 x 1 + 18
27 = 18 x 1 + 9
18 = 9 x 2 + 0
So, HCF (45, 27) = 9
d = 9 = 27x + 45y
From above steps, we have:
9 = 27 - 18 x 1
= 27 - (45 - 27 x 1) x 1
= 27 x 2 + 45 (-1)
Comparing this with given relation, we get
x = 2 and y = -1
Answered by Yasmeen Khan | 30 May, 2021, 11:25: AM
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