CBSE Class 10 Answered
If a freely falling body travels in the last second a distance equal to the distance travelled by it in first 3 seconds, then find the time of its travel.( in seconds)
Asked by acv27joy | 21 Apr, 2018, 07:15: PM
Expert Answer
Distance travelled in first 3 seconds = (1/2)gt2 = (1/2)×9.8×9 = 44.1 m
Let t be the time taken to travel the total height;
velocity at (t-1)th second = g×(t-1);
distance travelled at the last second = g(t-1)-(1/2)g = g×(t-1.5) = 44.1;
hence t = (44.1/9.8)+0.5 = 5 s
Answered by Thiyagarajan K | 21 Apr, 2018, 08:51: PM
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