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ICSE Class 9 Answered

I have a doubt on this question:  The time period of a simple pendulum on earth is 2 s. What will be the time period of same pendulum when it is brought on moon? (hint: value of g at moon is 1/6 of value of g at earth’s surface).  
Asked by alonso.bobbyj | 25 Jun, 2021, 04:47: PM
Expert Answer
Time period T of simple pendulam , T = 2π begin mathsize 14px style square root of L over g end root end style , where L is length of penulam and g is acceleration due to gravity
Let Te is time period on earth , Tm is time period on moon , ge is acceleration due to gravity on earth and gm is that on moon.
 
Since time period is inversely proportional to square root of acceleration due to gravity , we get
 
begin mathsize 14px style T subscript m over T subscript e space equals space square root of g subscript e over g subscript m end root space equals space square root of fraction numerator g subscript e over denominator left parenthesis 1 divided by 6 right parenthesis g subscript e end fraction end root space almost equal to 2.45 space end style
Hence time period of simple pendulam on moon, Tm = 2 × 2.45 = 4.9 s 
Answered by Thiyagarajan K | 25 Jun, 2021, 05:40: PM

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