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ICSE Class 9 Answered

Calculate time period of a simple pendulum of length 1.12m on the surface of moon. The acceleration due to gravity on surface of moon is 1/6th of the acceleration due to gravity on earth.  
Asked by shresthsingal | 04 Jan, 2020, 06:27: PM
Expert Answer
l = 1.12 m 
acceleration due to gravity on moon = acceleration due to gravity on the earth/6 
am = 9.8/6
 
We know, 
T = 2∏(√l/g) = 2 x(22/7) x √ (1.12 x 6/9.8) = 5.20 s 
 
Thus, time period of simple pendulum will be 5.20 s 
Answered by Shiwani Sawant | 05 Jan, 2020, 09:43: PM

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