ICSE Class 9 Answered
Calculate time period of a simple pendulum of length 1.12m on the surface of moon. The acceleration due to gravity on surface of moon is 1/6th of the acceleration due to gravity on earth.
Asked by shresthsingal | 04 Jan, 2020, 06:27: PM
Expert Answer
l = 1.12 m
acceleration due to gravity on moon = acceleration due to gravity on the earth/6
am = 9.8/6
We know,
T = 2∏(√l/g) = 2 x(22/7) x √ (1.12 x 6/9.8) = 5.20 s
Thus, time period of simple pendulum will be 5.20 s
Answered by Shiwani Sawant | 05 Jan, 2020, 09:43: PM
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