CBSE Class 10 Answered
How to find the zeros of x2-2x-8
Asked by vishakhatania | 05 May, 2020, 01:14: PM
Expert Answer
Given polynomial is P(x)=x2-2x-8
Take P(x)=0
x2-2x-8=0
x2-4x+2x-8=0
x(x-4)+2(x-4)=0
(x-4)(x+2)=0
x=4 or x=-2
Answered by Renu Varma | 05 May, 2020, 07:08: PM
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