# CBSE Class 10 Answered

**How to find the zeros of x2-2x-8**

Asked by vishakhatania | 05 May, 2020, 01:14: PM

Expert Answer

Given polynomial is P(x)=x

^{2}-2x-8Take P(x)=0

x

^{2}-2x-8=0x

^{2}-4x+2x-8=0x(x-4)+2(x-4)=0

(x-4)(x+2)=0

x=4 or x=-2

Answered by Renu Varma | 05 May, 2020, 07:08: PM

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