given- cube of side 20 cm and density 650 kg cubic meter. To find- distance -from the water level
Asked by ardas1994 | 8th Feb, 2010, 07:36: PM
The buoyancy force balances the weight of the cube.
ρsVsg = xρwVsg,
where x is the volume fraction submerged in water, and other symbols have usual meaning.
x = ρs/ρw = 650/1000 = 0.35
Vsubmerged/Vs = 0.35
Ah/0.2A = 0.35, where h is the height of cube submerged in water.
h = 0.07 m = 7 cm.
So 13 cm would the So called distance from water level.
Answered by | 9th Feb, 2010, 11:34: AM
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