given- cube of side 20 cm and density 650 kg cubic meter. To find- distance -from the water level

Asked by ardas1994 | 8th Feb, 2010, 07:36: PM

Expert Answer:


The buoyancy force balances the weight of the cube.

ρsVsg = xρwVsg,

where x is the volume fraction submerged in water, and other symbols have usual meaning.

x = ρsw = 650/1000 = 0.35

Vsubmerged/Vs = 0.35

Ah/0.2A = 0.35, where h is the height of cube submerged in water.

h = 0.07 m = 7 cm.

So  13 cm would the So called distance from water level.

Regards,

Team,

TopperLearning.

Answered by  | 9th Feb, 2010, 11:34: AM

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