FROM A POINT IN THE INTERIOR OF AN EQUILATERAL TRIANGLE PERPENDICULARS ARE DRAWN ON 3 SIDES.THE LENGTHS OF PERPENDICULARS ARE 14CM,10CM AND 6 CM.FIND THE AREA OF TRIANGLE

Asked by vrishti TOKAS | 28th Jul, 2015, 08:25: PM

Expert Answer:

A r e a space o f space A B C space equals space A r e a space o f space A O B space plus space A r e a space o f space B O C space plus space A r e a space o f space A O C rightwards double arrow fraction numerator square root of 3 over denominator 4 end fraction a squared equals 1 half a cross times 6 plus 1 half a cross times 14 plus 1 half a cross times 10 rightwards double arrow fraction numerator square root of 3 over denominator 4 end fraction a squared equals 1 half a cross times 30 rightwards double arrow a equals fraction numerator 60 over denominator square root of 3 end fraction equals 20 square root of 3 A r e a space o f space t h e space t r i a n g l e space i s space fraction numerator square root of 3 over denominator 4 end fraction a squared equals fraction numerator square root of 3 over denominator 4 end fraction cross times open parentheses 20 square root of 3 close parentheses squared equals 300 square root of 3 space s q u a r e space u n i t s.

Answered by satyajit samal | 29th Jul, 2015, 11:40: AM

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