From 200 mg of CO? , 10 to the power 21 molecules are removed. How many moles of CO? are left ?
Asked by MANISHA MOHANTY | 28th Dec, 2011, 07:46: PM
Expert Answer:
No. of moles of CO in 200 mg = 200 x10-3/28
= 0.0071 mole
No. of molecules in 0.0071 mole of CO = 0.0071 x 6.022 x1023
=4.28 x 1021 molecules of CO
Since, 1021 molecules are removed, therefore number of molecule remaining are 3.28 x1021
No. of moles of CO in 200 mg = 200 x10-3/28
= 0.0071 mole
No. of molecules in 0.0071 mole of CO = 0.0071 x 6.022 x1023
=4.28 x 1021 molecules of CO
Since, 1021 molecules are removed, therefore number of molecule remaining are 3.28 x1021
Answered by | 29th Dec, 2011, 10:14: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change