For the equation 3 x squared plus p x plus 3 equals 0, p>0, if one of the root is square of the other then possible value of p?

Asked by aahnik.mohanty | 10th Jun, 2019, 08:30: PM

Expert Answer:

3x2 + px + 3 = 0 and p > 0
Let r and r2 be the roots of the quadratic equation.
r + r2 = -p/3 and r3 = 1 
r3 = 1 
r3 - 1 = 0
(r - 1)(r2 + r + 1) = 0
r = 1 rejected as to p > 0
r2 + r + 1 = 0
-p/3 = -1
p = 3
 
 
 

Answered by Sneha shidid | 11th Jun, 2019, 10:09: AM