For the equation , p>0, if one of the root is square of the other then possible value of p?

### Asked by aahnik.mohanty | 10th Jun, 2019, 08:30: PM

Expert Answer:

### 3x^{2} + px + 3 = 0 and p > 0
Let r and r^{2} be the roots of the quadratic equation.
r + r^{2} = -p/3 and r^{3} = 1
r^{3} = 1
r^{3} - 1 = 0
(r - 1)(r^{2} + r + 1) = 0
r = 1 rejected as to p > 0
r^{2} + r + 1 = 0
-p/3 = -1
p = 3

^{2}+ px + 3 = 0 and p > 0

^{2}be the roots of the quadratic equation.

^{2}= -p/3 and r

^{3}= 1

^{3}= 1

^{3}- 1 = 0

^{2}+ r + 1) = 0

^{2}+ r + 1 = 0

### Answered by Sneha shidid | 11th Jun, 2019, 10:09: AM

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