Asked by  | 22nd Sep, 2008, 07:43: PM

Expert Answer:

B2-4AC = ( 11(a+b+c) )2 - 4* 2(a-b)*(-3)(a-b) =121(a+b+c)2 + 24 (a-b)2

here we can see that B2-4AC>0 since both the terms are square terms.

so roots of this equations are real and unequal since B2-4AC is not a perfect square.

Answered by  | 22nd Sep, 2008, 10:35: PM

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