CBSE Class 11-science Answered
FIND
Asked by | 22 Sep, 2008, 07:29: PM
Expert Answer
from given conditions a+b = -p and ab = 1 and c+d = -q and cd = 1
E = (a-c)(b-c)(a+d)(b+d)
=(ab-c(a+b) + c2) (ab+d(a+b)+d2 )
=(1+pc+c2)(1-pd+d2)
now x2+qx+1=0 has its roots as c and d
so c2+qc+1=0 and d2+qd+1=0
i.e. c2+1=-qc and d2+1=-qd
so E = (pc-qc)(-pd-qd)=-(p-q)(p+q)cd=-(p2-q2)
Answered by | 23 Sep, 2008, 01:15: AM
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