find

Asked by shekhar14351 | 19th Feb, 2010, 11:01: PM

Expert Answer:

The heat required to increase the temperature of ice to 0 °C and melt it is,

= mCpT + mλ= (5)(0.5)(10) + (5)(80) = 425 cal

The heat that can supplied by, water at 60 °C,

= mCpT = (20)(1)(60 - 0) = 1200 cal

So after providing 425 cal as required by first calculation, 1200 - 425 = 775 cal are left with the TOTAL amount of water (20gm + 5 gm of melted ice).

775 = mCpT = (25)(1)(T - 0)

T = 31 °C.

The final temperature of the mixture would be, 31 °C.

Regards,

Team,

TopperLearning.

 

Answered by  | 20th Feb, 2010, 06:19: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.