CBSE Class 11-science Answered

The heat required to increase the temperature of ice to 0 °C and melt it is,

= mC_pT + mλ= (5)(0.5)(10) + (5)(80) = 425 cal

The heat that can supplied by, water at 60 °C,

= mC_pT = (20)(1)(60 - 0) = 1200 cal

So after providing 425 cal as required by first calculation, 1200 - 425 = 775 cal are left with the TOTAL amount of water (20gm + 5 gm of melted ice).

775 = mC_pT = (25)(1)(T - 0)

T = 31 °C.

The final temperature of the mixture would be, 31 °C.

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