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# CBSE Class 11-science Answered

a body cools from 90°c to 70°c in 5minutes. temperature of surrounding is 30°c. its temperature after next 10 min is
Asked by manjushri30nov | 31 Dec, 2023, 07:48: PM

From Newton's law of cooling , we get temperature T(t) as a function of time when it cools from initial temperature To is

T(t) = Ts + ( To - Ts ) e-k t . ........................(1)

where Ts is temperature of surroundings .

If T(t) = 70o C after t = 5 min = 300 s , then we get from eqn.(1) as

---------------------------------------------

When the object is cooling after reaching 70o C , temperature after 5 minutes is calculated from eqn.(1)

When the object is cooling after reaching 56.7o C , temperature after 5 minutes is calculated from eqn.(1)

Hence , temperature after 10 minutes when the object is colling from 70o C is 47.8 oC

Answered by Thiyagarajan K | 01 Jan, 2024, 12:51: PM

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