find the smallest square number that is divisible by each of the numbers 7 , 15 and 21

Asked by deepsikhab71.8cpsb | 21st Jun, 2021, 06:03: PM

Expert Answer:

 
 7   =  7 × 1
15 =  3 × 5
21 =  3 × 7
 
 
LCM(7, 15, 21) = 3 × 5 × 7 = 105
 

105 = 3 × 5 × 7
 
To make 105 a square number, we will multiply it by 3 × 5 × 7 = 105 , we get
 
 
105 × 105  = 11025
 
So, 11025 is the smallest square number, which is divisible by 7, 15 and 21.

Answered by Yasmeen Khan | 21st Jun, 2021, 09:08: PM