# CBSE Class 8 Answered

**find the smallest square number that is divisible by each of the numbers 7 , 15 and 21**

Asked by deepsikhab71.8cpsb | 21 Jun, 2021, 06:03: PM

Expert Answer

7 = 7 × 1

15 = 3 × 5

21 = 3 × 7

LCM(7, 15, 21) = 3 × 5 × 7 = 105

105 = 3 × 5 × 7

To make 105 a square number, we will multiply it by 3 × 5 × 7 = 105 , we get

105 × 105 = 11025

So, 11025 is the smallest square number, which is divisible by 7, 15 and 21.

Answered by Yasmeen Khan | 21 Jun, 2021, 09:08: PM

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