CBSE Class 8 Answered
Find the smallest number by which 5103 must be divided to get a perfect square.
Asked by Topperlearning User | 19 Feb, 2014, 01:30: PM
First of all we will find the prime factors of 5103.
|
|
3 |
5103 |
3 |
1701 |
3 |
567 |
3 |
189 |
3 |
63 |
3 |
21 |
7 |
7 |
|
1 |
5103 = 3 x 3 x 3 x 3 x 3 x 3 x 7
Here, prime factor 7 does not have its pair.
If we divide the number 5103 by 7, then the number will become a perfect square. Therefore, 5103 has to be divided by 7 to obtain a perfect square.
Answered by | 19 Feb, 2014, 03:30: PM
Concept Videos
CBSE 8 - Maths
Asked by deepsikhab71.8cpsb | 21 Jun, 2021, 06:03: PM
CBSE 8 - Maths
Asked by deepasathishdav | 15 Jun, 2021, 03:55: PM
CBSE 8 - Maths
Asked by raghuvanshisuraj786 | 21 Oct, 2020, 08:46: AM
CBSE 8 - Maths
Asked by raghuvanshisuraj786 | 20 Oct, 2020, 11:10: AM
CBSE 8 - Maths
Asked by Trisha Gupta | 04 Sep, 2019, 01:34: PM
CBSE 8 - Maths
Asked by Topperlearning User | 19 Feb, 2014, 01:30: PM
CBSE 8 - Maths
Asked by Topperlearning User | 19 Feb, 2014, 01:30: PM
CBSE 8 - Maths
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM