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CBSE Class 11-science Answered

Find the molality of 98%(m/v) of H2SO4 solution.density of solution is 1.98g/cc
Asked by Sunita | 28 Mar, 2019, 09:27: AM
answered-by-expert Expert Answer
Givn:
 
H2SO4 = 98 % m/v
 
That is 98 g of H2SO4 in 100 ml 
 
Density =1.98g/cc
 
We konw,
 
Density space equals space fraction numerator Mass space over denominator Volume end fraction space space space 1.98 space space equals space fraction numerator Mass over denominator 100 space end fraction Mass space equals space 198 space straight g Mass space of space solvent space equals space 198 space minus space 98 space space space space space space space space space space space space space space space space space space space space space space space space space equals space 100 space gm space space space space space space space space space space space space space space space space space space space space space space space space space equals space 0.1 space kg Also comma No. space of space moles space equals space fraction numerator Weight over denominator Molecular space weight end fraction space space space space space space space space space space space space space space space space space space space space space space equals 98 over 98 No. space of space moles space equals space 1 space mol Molality space equals space fraction numerator No. space of space moles space over denominator Weight space of space solvent space in space kg end fraction space space space space space space space space space space space space equals fraction numerator 1 over denominator 0.1 end fraction Molality space equals space 10 space straight m space space space space space
 
Molality of the solution is 10 m.
Answered by Varsha | 28 Mar, 2019, 11:11: AM

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