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Find the equation of the plane passing through the line of intersection of the planes 3x – 5y + 4z + 11 = 0, 2x – 7y + 4z – 3 = 0 and the point (– 2, 1, 3).
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM Expert Answer

The equation of the plane passing through the line of intersection of the planes 3x – 5y + 4z + 11 = 0, 2x – 7y + 4z – 3 = 0 is: .
Also, the plane passing through the point (– 2, 1, 3), Now, the required equation of the plane is: Answered by | 04 Jun, 2014, 03:23: PM
CBSE 12-science - Maths ANSWERED BY EXPERT
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Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM ANSWERED BY EXPERT
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Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM ANSWERED BY EXPERT