Find the equation of the circle passing through the point of intersection of the lines x + 3y = 0 and 2x - 7y = 0 and whose centre is the point of intersection of the lines x + y + 1 = 0 and x - 2y + 4 = 0.

Asked by Topperlearning User | 25th Apr, 2014, 09:12: AM

Expert Answer:

Point of intersection of the lines x + 3y = 0 and 2x - 7y = 0 is x = 0, y = 0. This implies that the circle passes through the origin centre lies on the point of intersection of the lines

x + y + 1= 0

x - 2y + 4 = 0

Thus centre is (-2,1)

Distance between any point on the circumference of the circle and the centre is the radius,

Answered by  | 25th Apr, 2014, 11:12: AM

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