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Find the current in each resistor Asked by najeeb.razvi | 09 Aug, 2021, 06:45: PM Expert Answer In the given circuit R1 and R4 are in series .
Hence Equivalent resistance R7 = 4Ω replaces resistors R1 and R4 in the circuit shown above.

Similarly , in the given circuit, R3 and R5 are in parallel.
Hence Equivalent resistance R6 = 4Ω replaces resistors R3 and R5 in the circuit shown above.

Let us assume the current distribution as shown in figure.

If we apply Kirchoff's voltage law to the loop ABEFA , we get 1 + 4 3 + 2 = 2   or 1 = - 3   ............................ (1)
If we apply Kirchoff's voltage law to the loop BCDEB , we get 1 + 4 2 + 2 = 2   or 1 = - 2  ...........................(2)
At node B , if we apply Kirchoff's current law , we get 1 2 3  ...............................(3)
From equations (1), (2) and (3) , we get , 1 = 2  = 3 = 0
Hence current through all resistors is zero
Answered by Thiyagarajan K | 09 Aug, 2021, 08:33: PM

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