Find the area & perimeter of a rhombus whose diagonals measure 28cm and 96cm. 

Asked by Cl_narayan | 30th Sep, 2019, 09:38: PM

Expert Answer:

The diagonals of a rhombus are 28 cm and 96 cm. 
Area of rhombus = 1/2 of product of diagonals = 1/2 × 28 × 96 = 1344 cm2
The diagonals are perpendicular bisectors of each other.
In triangle AOB,
using Pythagoras
AO2 + OB2 = AB2 
482 + 142 = AB2 
AB2 = 2500
AB = 50 cm
The side of a rhombus is 50 cm.
Perimeter of a rhombus = 50 × 4 = 200 cm

Answered by Sneha shidid | 1st Oct, 2019, 09:30: AM