find the area of quardilateral ABCD where AB=9CM,BC=10CM,CD=12CM,DA=11CMAND line AB||lineCD
Asked by
| 4th Feb, 2012,
09:18: AM
Expert Answer:
Drawtwo perpendiculars from A and B to CD that intersect CD at P , Q respectively
Let DP be x , CP be 3-x , AP = h
so , x2 + h2 = 121 , (x-3)2 + h2 = 100
On solving we get h = root(96)
area = 1/2 * (9 + 12) * root(96) = 42root(6) cm2
Answered by
| 4th Feb, 2012,
03:45: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change