find the area of quardilateral ABCD where AB=9CM,BC=10CM,CD=12CM,DA=11CMAND line AB||lineCD
Asked by | 4th Feb, 2012, 09:18: AM
Expert Answer:
Drawtwo perpendiculars from A and B to CD that intersect CD at P , Q respectively
Let DP be x , CP be 3-x , AP = h
so , x2 + h2 = 121 , (x-3)2 + h2 = 100
On solving we get h = root(96)
area = 1/2 * (9 + 12) * root(96) = 42root(6) cm2
Answered by | 4th Feb, 2012, 03:45: PM
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