Find the amount of 98% pure Na2CO3 required to prepare 5 litres of 1 N solution

Asked by  | 24th Jun, 2008, 09:13: PM

Expert Answer:

1 N solution requires 106/2 =53 g/1litre.

for 100% purity its 53 g, for 98 % its 54.08 g. is needed for 1 N solution.

Hence for 5 litre of 98% pure sodium carbonate  needs 5 X 54.08 =   270.4 g

Answered by  | 7th Jul, 2008, 08:14: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.