Find the amount of 98% pure Na2CO3 required to prepare 5 litres of 1 N solution
Asked by | 24th Jun, 2008, 09:13: PM
Expert Answer:
1 N solution requires 106/2 =53 g/1litre.
for 100% purity its 53 g, for 98 % its 54.08 g. is needed for 1 N solution.
Hence for 5 litre of 98% pure sodium carbonate needs 5 X 54.08 = 270.4 g
Answered by | 7th Jul, 2008, 08:14: PM
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