find no. of ions each of Na+ and SO4 2- present in 142 g of Na2SO4......plzz explain....

Asked by  | 16th Aug, 2008, 11:57: AM

Expert Answer:

No. of ions each of Na+ and SO4 2- present in 142 g of Na2SO4i is :

no. of Na+=2 X6.023 x 1023

no. of SO4 2- = 6.023 x 10 23

Na2SO42Na+    +       SO4 2-   

 

Answered by  | 18th Aug, 2008, 09:54: AM

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