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JEE Class main Answered

Find internal energy
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Asked by ashutosharnold1998 | 03 Nov, 2019, 20:22: PM
answered-by-expert Expert Answer
Given:
 
For the change:
 
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ΔH = H1+ H2 
 
n = 1 mole
 
T = 100 °C
 
H1 = nCdT
 
    = 1× (-4.2)×18×100
 
    = -7560 J/mol
 
    = -7.56 kJ/mol
 
H2 = -6 kJ/mol
 
ΔH = -7.56 + (-6)
 
ΔH = -13.56 kJ/mol
 
In the process the volume change is negligible
 
 Therefore, ΔH = ΔU +PΔV
 
ΔV =0
 
Change in internal energy = -13.56 kJ/mol
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