NEET Class neet Answered
find binding energy
Asked by adititiwari601 | 13 Jun, 2022, 07:44: AM
Expert Answer
Binding energy = Δm c2
where Δm is mass defect and c is speed of light
Binding energy = ( 3.5 amu ) × ( 1.66 × 10-27 kg/amu ) × ( 9 × 1016 m/s2 )
Binding energy = 5.229 × 10-10 J
1 MeV = 1.602 × 10-13 J
Binding energy in MeV = ( 5.229 × 10-10 ) / ( 1.602 × 10-13 ) = 3264 MeV
Answered by Thiyagarajan K | 13 Jun, 2022, 08:23: AM
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