CBSE Class 10 Answered
Find a smallest number of 5 digits which is exactly divisible by 24,36 and 48.
Asked by Rohit | 02 Jun, 2012, 04:50: PM
Expert Answer
Smallest number of 5 digits = 10000
Any number which has to be divisible by 24, 36, 48 has to be a common multiple of these.
So, LCM (24, 36, 48) = 288
10000 is not divisible by 288.
So the required number has to be greater than 10000.
On dividing 10000 with 288, we get quotient as 34 and remainder as 208.
So, the required number is 288 x 35 = 10080
Answered by | 03 Jun, 2012, 03:05: PM
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