Asked by sahilcoolest | 2nd Mar, 2010, 12:26: PM
let the circles with centers O and O' intersect at A and B resply.
consider triangleOAB by joining O to A and O to B.
in triangle OAB,OA=OB.. radii
angle OAB=angle OBA..(i)
in triangle OAB,
angle O'AB=angle O'BA..(ii)
adding resply the RHS and LHS of (i) and (ii)
angle OAO'=angle OBO'
so we get that
angle subtended by the line OO' joining the centers O and O' ,
subtends equal angles at the points A and B of intersection of the circles.
Answered by | 2nd Mar, 2010, 01:50: PM
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