Asked by rijutar | 20th Jan, 2012, 03:18: PM

Expert Answer:

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On differentiating tan(x3+2x+5),we get Sec2(x3+2x+5)X(3x2+2)
Also,on differentiating sec7x,we get 7sec6x(secx.tanx)=7 sec7xtanx

Answered by  | 20th Jan, 2012, 03:38: PM

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