CBSE Class 11-science Answered
3 ka 3 par
Asked by kanishkatutejasirsa | 09 Mar, 2024, 11:08: AM
Expert Answer
y = { log [ cos(x) ] }2
Let y = u2 , where u = log w and w = cos(x)
By chain rule
...................... (1)
dy/du = 2 u = 2 log [ cos(x) ]
u = log (w) = 0.434 ln(w)
du/dw = d/dw [ 0.434 ln(w) ] = 0.434 (1/w ) = 0.434 ( 1/cos(x) )
dw/dx = -sin(x)
Hence from eqn.(1)
dy/dx = - 2 log [ cos(x) ] ( 1/ cos(x) ) sin(x)
dy/dx = - 0.868 log( cos(x) ) tan(x)
Answered by Thiyagarajan K | 09 Mar, 2024, 02:43: PM
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