Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

Evaluate fraction numerator left square bracket s e c theta c o s e c left parenthesis 90 minus theta right parenthesis minus t a n theta c o t left parenthesis 90 minus theta right parenthesis plus s i n squared 55 degree s i n squared 35 degree right square bracket over denominator left parenthesis tan 10 degree tan 20 degree tan 60 degree tan 70 degree tan 80 degree right parenthesis end fraction
Asked by pkirankumar4321 | 19 Sep, 2015, 08:51: PM
answered-by-expert Expert Answer
begin mathsize 14px style fraction numerator s e c theta cos e c left parenthesis 90 minus theta right parenthesis minus tan theta c o t left parenthesis 90 minus theta right parenthesis plus sin squared 55 plus sin squared 35 over denominator tan 10. tan 20. tan 60. tan 70. tan 80 end fraction equals fraction numerator s e c theta s e c theta minus t a n theta tan theta plus s i n squared 55 plus s i n squared left parenthesis 90 minus 55 right parenthesis over denominator t a n 10. t a n 20. t a n 60. t a n left parenthesis 90 minus 20 right parenthesis. t a n left parenthesis 90 minus 10 right parenthesis end fraction equals fraction numerator s e c squared theta minus t a n squared theta plus s i n squared 55 plus cos squared 55 over denominator t a n 10. t a n 20. square root of 3. c o t 20. c o t 10 end fraction equals fraction numerator 1 plus tan squared theta minus t a n squared theta plus 1 over denominator t a n 10. t a n 20. square root of 3. begin display style fraction numerator 1 over denominator tan 20 end fraction end style. begin display style fraction numerator 1 over denominator tan 10 end fraction end style end fraction equals fraction numerator 2 over denominator square root of 3 end fraction end style
Answered by Rashmi Khot | 20 Sep, 2015, 03:18: PM

Application Videos

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
CBSE 10 - Maths
the poles AB and CD of different heights are standing vertically on the ground level from a point P on the line joining the foots of the pole on the level of ground the angle of elevation to the top of the pole are founded to be complementary the of the CD and the distance PD 20√3m and 20m respectively if the BP is 10m then find the length of AB and the distance AC between the tpo of the poles
Asked by mraniruddha03 | 02 Apr, 2024, 06:44: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Prove that-- tanA+secA-1/tanA-secA+1 = 1+sinA/cosA
Asked by priyanshdhiman2008 | 25 Dec, 2023, 03:12: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
tan15° + tan30° + tan15° ×tan30°=1
Asked by deepakverma786024 | 18 Dec, 2022, 05:43: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Given that sin tita =a/b,then tan tita is equal to
Asked by Bavashreelogasundaram | 22 Sep, 2022, 08:26: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
(1+tanA+secA) (1+cotA-cosecA)=?
Asked by sahanahosamani2005 | 25 Nov, 2020, 10:58: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
question
question image
Asked by arindeep.singh | 10 Sep, 2020, 07:04: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
trigonometry
question image
Asked by choudharylakshay786 | 16 May, 2020, 12:56: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
Proove that (CotA+CosecA-1)/(CotA-CosecA+1) = (1+CosA)/SinA
Asked by kssvsv2011 | 09 May, 2020, 08:44: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
maths sums
question image
Asked by gurvinderr043 | 12 Apr, 2020, 08:18: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Maths
prove that cos theta by 1-tan theta+sin theta by 1- cot theta equals to sin theta+ cos theta
Asked by gurunath196107 | 07 Apr, 2020, 04:21: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×