Equal masses of oxygen,hydrogen and methane are taken in a container in identical condition.Find the ratio of volumes of the gases.

Asked by pb_ckt | 29th May, 2019, 11:40: PM

Expert Answer:

The molecular weights of given mixture of gases are
1. Oxygen = 32
2. Hydrogen = 2
3. Methane = 16
 
Since masses are equal, assume mass as x,
 
So By using formula,
 
   N o. space o f space m o l e s space equals fraction numerator m a s s over denominator M o l e c u l a r space w e i g h t end fraction   the no. of moles would be,

 
n left parenthesis O subscript 2 right parenthesis space equals space x over 32 space comma space space space space space space space n left parenthesis H subscript 2 right parenthesis space equals space x over 2 space comma space space space space space space space n left parenthesis C H subscript 4 right parenthesis space equals space x over 16

T h e space r a t i o space o f space t h i e r space v o l u m e space w i l l space b e
left parenthesis O subscript 2 right parenthesis space colon left parenthesis H subscript 2 right parenthesis space colon space left parenthesis C H subscript 4 right parenthesis space space equals space 1 space space colon space space 16 space space colon space space 2 space space

Answered by Ramandeep | 30th May, 2019, 10:38: AM