CBSE Class 12-science Answered
Equal and similar charges are placed on the earth and the moon. The value of charge required to neutralize their gravitational attraction is
Asked by Gaurav nagpal | 30 Jun, 2011, 07:58: PM
Expert Answer
According to the given condition is that
Coulombic repulsion = Gravitational attraction
(1/4??0)(q2/r2) = G m2/r2
q = sqrt (G m2 / 9 x 109)
So the value of charge can be calculated by substituting the values of G and mass of the charge.
Answered by | 01 Jul, 2011, 10:20: AM
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