Equal and similar charges are placed on the earth and the moon. The value of charge required to neutralize their gravitational attraction is

Asked by Gaurav nagpal | 30th Jun, 2011, 07:58: PM

Expert Answer:

According to the given condition is that 
 
Coulombic repulsion = Gravitational attraction
 
(1/4??0)(q2/r2) = G m2/r2
 
   q = sqrt (G m2 / 9 x 109)
 
So the value of charge can be calculated by substituting the values of G and mass of the charge.

Answered by  | 1st Jul, 2011, 10:20: AM

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