CBSE Class 10 Answered
determining k
Asked by meghapte | 18 Jan, 2010, 09:21: PM
Expert Answer
For the three points to be collinear, the following determinant must be zero, whose elements are,
First row: 5 2 1
Second row: k 3 1
Third row: G k 1
5(3-k)-2(k-G)+(k2-3G) = 0
k2 -7k +15-G = 0
k = [7±(49-4(15-G))]/2
= [7±(4G - 11)]/2
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Answered by | 19 Jan, 2010, 10:02: AM
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