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Asked by g_archanasharma | 01 Apr, 2019, 09:17: AM
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begin mathsize 12px style x squared plus 1 over x squared space equals space open parentheses x plus 1 over x close parentheses squared minus 2 end style
 
Hence if  f [x+(1/x) ] = x2 + (1/x2)  = [x+(1/x) ]2 -2
 
if we replace [x+(1/x) ] by x, then we have,  f(x) = x2 -2   for all x and x ≠ 0
Answered by Thiyagarajan K | 01 Apr, 2019, 12:08: PM

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