ICSE Class 10 Answered
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Asked by swainanirudha1 | 16 Nov, 2018, 04:04: PM
Net mass of water to be boiled= 25+1= 26kg
Change in temperature = 100-25 = 75 °C
Specific heat of water= 4186 J/kg °C
Heat required= MCT = 26×75×4186 = 8162700 joule
Answered by Ankit K | 16 Nov, 2018, 10:55: PM
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