Asked by rohit1993 | 2nd Jul, 2008, 03:32: PM
The distance SP = a(t2+1)
The distance SQ =a(1+1/t2)
Thus, 1/SP + 1/SQ = t2/a(t2+1) +1/a(t2+1) = 1/a.
hence, it is independent of t.
Answered by | 15th Jul, 2008, 05:17: PM
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