Asked by rohit1993 | 2nd Jul, 2008, 03:32: PM

Expert Answer:

The distance SP = a(t2+1)

The distance SQ =a(1+1/t2)

Thus, 1/SP + 1/SQ = t2/a(t2+1) +1/a(t2+1) = 1/a.

hence, it is independent of t.

Answered by  | 15th Jul, 2008, 05:17: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.