CBSE Class 10 Answered
coordinate geometry
Asked by | 12 Mar, 2009, 02:07: PM
Expert Answer
Let the coordinates of Circumcentre be (x,y) Now this is equidistant from all the three VERTICES namely
(3,0).(-1,-6), (4,-1)
Apply distance formula and equate the three distances
(x-3)2+y2 =(x+1)2+(y+6)2=(x-4)2+(y+1)2
Solve the three equations
(x-3)2+y2 =(x+1)2+(y+6)2
(x+1)2+(y+6)2=(x-4)2+(y+1)2 and (x-3)2+y2 = (x-4)2+(y+1)2
and obtain x,y.
Circumradius will be sqrt( (x-3)2+y2)
Answered by | 13 Mar, 2009, 09:51: AM
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