CBSE Class 8 Answered
We know that the diagonals of a rhombus bisect each other at right angles.
Let AC = 9 cm and BD = 7 cm
Steps of construction:
i) Draw AC = 9 cm.
ii) Draw the perpendicular bisector XY of AC, meeting AC at O.
iii) From O, cut off OB = (7 cm) = 3.5 cm along OY and OD = (7 cm) = 3.5 cm along OX.
iv) Join AB, BC, CD and DA.
ABCD is the required rhombus.