Request a call back

conic sections --find eq of parabola that satisfies the given conditions focus(0,-3);directrix y=3?
Asked by | 07 Mar, 2008, 08:01: PM Expert Answer

Let P(x.y) be any point on the parabola having its focus at S(0, -3) and directrix as the line y-3=0. then

SP=PM, where PM is the length of perpendicular from P on the directrix.

this implies SP square = PM square

(x-0) square + (y+3) square=  (y-3) square

On simplifying, this implies the eqation of parabola is

x square = -12y

Answered by | 18 Mar, 2008, 07:03: PM
CBSE 11-science - Maths
Asked by ashwinikumar59 | 02 May, 2010, 08:08: AM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Sonal13 | 01 May, 2010, 12:42: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Sonal13 | 01 May, 2010, 12:40: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by ashwinikumar59 | 30 Apr, 2010, 03:21: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by ashwinikumar59 | 29 Apr, 2010, 07:48: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by Vishnusasidharan | 05 Apr, 2010, 08:12: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by satyakitopper | 21 Mar, 2010, 11:57: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by sahare | 10 Feb, 2010, 06:01: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by devendra.mittal | 05 Jan, 2010, 10:08: PM ANSWERED BY EXPERT
CBSE 11-science - Maths
Asked by devendra.mittal | 05 Jan, 2010, 10:01: PM ANSWERED BY EXPERT