Commercially available concentrated hydrochloric acid contains 38% HCl by mass- (i) What is the molarity of the solution (Density of solution= 1.19g/mol). (ii) What volume of concentrated HCl is required to make 1 litre of 0.1 molar strength.

  38% solution means 38 gms of HCl is present in 100 grams of solution

 

Density = 1.19g/cm³

 

Volume = Mass /Density

Volume= 100/1.19cm³=84.03 cm³

 

 

Moles= 38/98= 0.3877

 

Molarity= molesX1000/volume

 

Molarity = 0.3877X1000/84.03

 

Molarity = 387.7/84.03=4.61M

 

 

 

using

M₁ V₁= M ₂ V₂

4.61 X V₁= 1 X 0.1

V₁= 0.1/4.61

V₁= 0.0216 l

V₁= 21.6 ml