Commercially available concentrated hydrochloric acid contains 38% HCl by mass- (i) What is the molarity of the solution (Density of solution= 1.19g/mol). (ii) What volume of concentrated HCl is required to make 1 litre of 0.1 molar strength.
Asked by mesamit
| 31st Jul, 2010,
04:04: PM
Expert Answer:
38% solution means 38 gms of HCl is present in 100 grams of solution
Density = 1.19g/cm3
Volume = Mass /Density
Volume= 100/1.19cm3=84.03 cm3
Moles= 38/98= 0.3877
Molarity= molesX1000/volume
Molarity = 0.3877X1000/84.03
Molarity = 387.7/84.03=4.61M
using
M1 V1= M 2 V2
4.61 X V1= 1 X 0.1
V1= 0.1/4.61
V1= 0.0216 l
V1= 21.6 ml
Answered by
| 31st Jul, 2010,
08:20: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change