carbon reacts with oxygen to yield CO, depending on quantity of oxygen available per mole of carbon. if excess of O2 is available after formation of CO, then CO2 is produced.

           

       

100g of oxygen is reacting with different amounts of carbon as given in the following questions. final out the number of moles of CO andCO2 in each of the follfwing cases.

1. 10g of carbon
2. 60g of carbon

First reaction C + 1/2 O₂ --> CO and second reaction, CO + 1/2 O₂ --> CO₂

1) For first reaction,

32 g O₂ requires 24 g C

100g O₂ requires 75 g C

But available C is 10 g, hence C is limiting agent.

12 g C means 1 mole hence 10 g C means 0.833 moles.

Now 1 mole of C produces 1 mole CO

Hence, 0.833 moles of C produces 0.833 moles of CO.

Also from second reaction, 1 mole of CO produces 1 mole of CO₂ , hence 0.833 moles of Co produce 0.833 moles of CO₂

2) For first reaction,

32 g O₂ requires 24 g C

100g O₂ requires 75 g C

60 g of carbon is available, hence C is limiting agent.

12 g C means 1 mole hence 60 g C means 5 moles.

As 1 mole of C produces 1 mole CO, hence, 5 moles of C pwill produce 5 moles of CO.

Form second reaction, 1 mole of CO produces 1 mole of CO₂

Hence, 5 moles of CO produce 5 moles of CO₂